X^2+2x-8=2x+1

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Solution for X^2+2x-8=2x+1 equation: 


Simplifying
X2 + 2x + -8 = 2x + 1

Reorder the terms:
-8 + X2 + 2x = 2x + 1

Reorder the terms:
-8 + X2 + 2x = 1 + 2x

Add '-2x' to each side of the equation.
-8 + X2 + 2x + -2x = 1 + 2x + -2x

Combine like terms: 2x + -2x = 0
-8 + X2 + 0 = 1 + 2x + -2x
-8 + X2 = 1 + 2x + -2x

Combine like terms: 2x + -2x = 0
-8 + X2 = 1 + 0
-8 + X2 = 1

Solving
-8 + X2 = 1

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + X2 = 1 + 8

Combine like terms: -8 + 8 = 0
0 + X2 = 1 + 8
X2 = 1 + 8

Combine like terms: 1 + 8 = 9
X2 = 9

Simplifying
X2 = 9

Take the square root of each side:
X = {-3, 3}

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